A capacitor has a capacitance of 10 μF and is charged to a potential of 50 V. Wh

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Question: A capacitor has a capacitance of 10 μF and is charged to a potential of 50 V. What is the energy stored in the capacitor?

Options:

Correct Answer: 0.025 J

Solution:

Energy stored U = 1/2 * C * V² = 1/2 * 10 × 10^-6 F * (50 V)² = 0.0125 J.

A capacitor has a capacitance of 10 μF and is charged to a potential of 50 V. What is the energy stored in the capacitor?

A capacitor has a capacitance of 10 μF and is charged to a potential of 50 V. What is the energy stored in the capacitor?

Step 1: Identify the formula for the energy stored in a capacitor, which is U = 1/2 * C * V².
Step 2: Note the values given: capacitance (C) = 10 μF and voltage (V) = 50 V.
Step 3: Convert the capacitance from microfarads to farads: 10 μF = 10 × 10^-6 F.
Step 4: Substitute the values into the formula: U = 1/2 * (10 × 10^-6 F) * (50 V)².
Step 5: Calculate (50 V)², which is 2500 V².
Step 6: Multiply 10 × 10^-6 F by 2500 V² to get 0.025 J.
Step 7: Finally, multiply by 1/2: U = 1/2 * 0.025 J = 0.0125 J.

Capacitance and Energy Storage – Understanding how capacitors store energy based on their capacitance and the voltage across them.