What is the electric potential due to a point charge of 5 μC at a distance of 2 m?
Practice Questions
1 question
Q1
What is the electric potential due to a point charge of 5 μC at a distance of 2 m?
0 V
2250 V
1125 V
4500 V
Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (2 m) = 2250 V.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the electric potential due to a point charge of 5 μC at a distance of 2 m?
Solution: Electric potential V = k * q / r = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (2 m) = 2250 V.
Steps: 6
Step 1: Identify the formula for electric potential (V) due to a point charge, which is V = k * q / r.
Step 2: Identify the values needed for the calculation: k (Coulomb's constant) = 9 × 10^9 N m²/C², q (the charge) = 5 μC = 5 × 10^-6 C, and r (the distance) = 2 m.
Step 3: Substitute the values into the formula: V = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (2 m).
