What is the electric potential due to a point charge of 5 μC at a distance of 2

Practice Questions

Q1
What is the electric potential due to a point charge of 5 μC at a distance of 2 m?
  1. 0 V
  2. 2250 V
  3. 1125 V
  4. 4500 V

Questions & Step-by-Step Solutions

What is the electric potential due to a point charge of 5 μC at a distance of 2 m?
  • Step 1: Identify the formula for electric potential (V) due to a point charge, which is V = k * q / r.
  • Step 2: Identify the values needed for the calculation: k (Coulomb's constant) = 9 × 10^9 N m²/C², q (the charge) = 5 μC = 5 × 10^-6 C, and r (the distance) = 2 m.
  • Step 3: Substitute the values into the formula: V = (9 × 10^9 N m²/C²) * (5 × 10^-6 C) / (2 m).
  • Step 4: Calculate the numerator: 9 × 10^9 * 5 × 10^-6 = 45 × 10^3 = 45000.
  • Step 5: Divide the result by the distance (2 m): 45000 / 2 = 22500.
  • Step 6: The final result is V = 2250 V.
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