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A is 5 years older than B. If the sum of their ages is 45 years, how old is B?
A is 5 years older than B. If the sum of their ages is 45 years, how old is B?
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Q1
A is 5 years older than B. If the sum of their ages is 45 years, how old is B?
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Let B's age be x. Then A's age is x + 5. So, x + (x + 5) = 45, which gives 2x + 5 = 45, hence 2x = 40, x = 20. Therefore, B is 20 years old.
Questions & Step-by-step Solutions
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Q
Q: A is 5 years older than B. If the sum of their ages is 45 years, how old is B?
Solution:
Let B's age be x. Then A's age is x + 5. So, x + (x + 5) = 45, which gives 2x + 5 = 45, hence 2x = 40, x = 20. Therefore, B is 20 years old.
Steps: 7
Show Steps
Step 1: Let B's age be represented by the variable x.
Step 2: Since A is 5 years older than B, we can express A's age as x + 5.
Step 3: The problem states that the sum of their ages is 45 years. We can write this as an equation: x + (x + 5) = 45.
Step 4: Simplify the equation: Combine like terms to get 2x + 5 = 45.
Step 5: To isolate the variable, subtract 5 from both sides of the equation: 2x = 40.
Step 6: Now, divide both sides by 2 to solve for x: x = 20.
Step 7: Since x represents B's age, we conclude that B is 20 years old.
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