Ten years ago, the age of A was twice the age of B. If A is now 30 years old, ho

Practice Questions

Q1
Ten years ago, the age of A was twice the age of B. If A is now 30 years old, how old is B now?
  1. 10
  2. 15
  3. 20
  4. 25

Questions & Step-by-Step Solutions

Ten years ago, the age of A was twice the age of B. If A is now 30 years old, how old is B now?
Correct Answer: 20
  • Step 1: Determine A's age 10 years ago. A is now 30 years old, so 10 years ago A was 30 - 10 = 20 years old.
  • Step 2: Understand the relationship between A's age and B's age 10 years ago. The problem states that 10 years ago, A's age was twice B's age.
  • Step 3: Set up the equation based on the relationship. If A was 20 years old, then B's age 10 years ago was 20 / 2 = 10 years old.
  • Step 4: Calculate B's current age. Since 10 years have passed, B is now 10 + 10 = 20 years old.
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