Ten years ago, the age of A was twice the age of B. If A is now 30 years old, ho

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Question: Ten years ago, the age of A was twice the age of B. If A is now 30 years old, how old is B now?

Options:

Correct Answer: 25

Solution:

Ten years ago, A was 30 - 10 = 20 years old. Therefore, B was 20 / 2 = 10 years old then. Now, B is 10 + 10 = 20 years old.

Ten years ago, the age of A was twice the age of B. If A is now 30 years old, how old is B now?

Ten years ago, the age of A was twice the age of B. If A is now 30 years old, how old is B now?

Correct Answer: 20

Step 1: Determine A's age 10 years ago. A is now 30 years old, so 10 years ago A was 30 - 10 = 20 years old.
Step 2: Understand the relationship between A's age and B's age 10 years ago. The problem states that 10 years ago, A's age was twice B's age.
Step 3: Set up the equation based on the relationship. If A was 20 years old, then B's age 10 years ago was 20 / 2 = 10 years old.
Step 4: Calculate B's current age. Since 10 years have passed, B is now 10 + 10 = 20 years old.

Age Relationships – Understanding how to relate the ages of two individuals over time.
Basic Arithmetic – Performing simple calculations to determine ages based on given conditions.