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What is the condition for a Wheatstone bridge to be in a balanced state?

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Question: What is the condition for a Wheatstone bridge to be in a balanced state?

Options:

  1. R1/R2 = R3/R4
  2. R1 + R2 = R3 + R4
  3. R1 - R2 = R3 - R4
  4. R1 * R4 = R2 * R3

Correct Answer: R1/R2 = R3/R4

Solution: 

The condition for balance is R1/R2 = R3/R4.

What is the condition for a Wheatstone bridge to be in a balanced state?

Practice Questions

Q1
What is the condition for a Wheatstone bridge to be in a balanced state?
  1. R1/R2 = R3/R4
  2. R1 + R2 = R3 + R4
  3. R1 - R2 = R3 - R4
  4. R1 * R4 = R2 * R3

Questions & Step-by-Step Solutions

What is the condition for a Wheatstone bridge to be in a balanced state?
  • Step 1: Understand that a Wheatstone bridge is a circuit used to measure unknown resistances.
  • Step 2: Identify the four resistors in the Wheatstone bridge: R1, R2, R3, and R4.
  • Step 3: Know that the bridge is balanced when the ratio of the resistances is equal.
  • Step 4: Write the condition for balance as R1 divided by R2 equals R3 divided by R4.
  • Step 5: This means that if you take the ratio of R1 to R2, it should be the same as the ratio of R3 to R4.
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