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If the emf of a cell is 2V and the potential gradient of the potentiometer wire
If the emf of a cell is 2V and the potential gradient of the potentiometer wire is 4 V/m, what will be the balancing length?
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Practice Questions
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Q1
If the emf of a cell is 2V and the potential gradient of the potentiometer wire is 4 V/m, what will be the balancing length?
0.5 m
1 m
0.25 m
0.75 m
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The balancing length is calculated as L = V / (potential gradient) = 2V / 4 V/m = 0.5 m.
Questions & Step-by-step Solutions
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Q
Q: If the emf of a cell is 2V and the potential gradient of the potentiometer wire is 4 V/m, what will be the balancing length?
Solution:
The balancing length is calculated as L = V / (potential gradient) = 2V / 4 V/m = 0.5 m.
Steps: 6
Show Steps
Step 1: Identify the emf of the cell, which is given as 2V.
Step 2: Identify the potential gradient of the potentiometer wire, which is given as 4 V/m.
Step 3: Use the formula for balancing length, which is L = V / (potential gradient).
Step 4: Substitute the values into the formula: L = 2V / 4 V/m.
Step 5: Perform the calculation: 2 divided by 4 equals 0.5.
Step 6: The unit of length is in meters, so the balancing length is 0.5 m.
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