If the emf of a cell is 2V and the potential gradient of the potentiometer wire

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Question: If the emf of a cell is 2V and the potential gradient of the potentiometer wire is 4 V/m, what will be the balancing length?

Options:

Correct Answer: 1 m

Solution:

The balancing length is calculated as L = V / (potential gradient) = 2V / 4 V/m = 0.5 m.

If the emf of a cell is 2V and the potential gradient of the potentiometer wire is 4 V/m, what will be the balancing length?

If the emf of a cell is 2V and the potential gradient of the potentiometer wire is 4 V/m, what will be the balancing length?

Step 1: Identify the emf of the cell, which is given as 2V.
Step 2: Identify the potential gradient of the potentiometer wire, which is given as 4 V/m.
Step 3: Use the formula for balancing length, which is L = V / (potential gradient).
Step 4: Substitute the values into the formula: L = 2V / 4 V/m.
Step 5: Perform the calculation: 2 divided by 4 equals 0.5.
Step 6: The unit of length is in meters, so the balancing length is 0.5 m.

Electromotive Force (emf) – The emf of a cell is the voltage provided by the cell when no current is flowing.
Potential Gradient – The potential gradient is the change in voltage per unit length along the potentiometer wire.
Balancing Length – The balancing length in a potentiometer is the length of the wire required to balance the emf of the cell.
Potentiometer Principle – A potentiometer measures the potential difference by balancing it against a known potential gradient.