In a potentiometer experiment, if the balancing length is found to be 50 cm for a cell of emf 1.5V, what is the potential gradient if the total length of the wire is 100 cm?
Practice Questions
1 question
Q1
In a potentiometer experiment, if the balancing length is found to be 50 cm for a cell of emf 1.5V, what is the potential gradient if the total length of the wire is 100 cm?
3 V/m
1.5 V/m
0.5 V/m
2 V/m
The potential gradient is V/L = 1.5V/0.5m = 3 V/m.
Questions & Step-by-step Solutions
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Q
Q: In a potentiometer experiment, if the balancing length is found to be 50 cm for a cell of emf 1.5V, what is the potential gradient if the total length of the wire is 100 cm?
Solution: The potential gradient is V/L = 1.5V/0.5m = 3 V/m.
Steps: 8
Step 1: Understand that the balancing length is the length of the wire where the voltage is equal to the emf of the cell.
Step 2: Note that the balancing length given is 50 cm, which is equal to 0.5 meters.
Step 3: The emf of the cell is given as 1.5V.
Step 4: The total length of the wire is 100 cm, which is equal to 1 meter.
Step 5: Calculate the potential gradient using the formula: Potential Gradient = Voltage / Length of wire.
Step 6: Substitute the values into the formula: Potential Gradient = 1.5V / 0.5m.
