A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipate

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Question: A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?

Options:

Correct Answer: 40 W

Solution:

Power (P) can be calculated using P = V^2 / R = 20^2 / 10 = 400 / 10 = 40 W.

A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?

A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?

Step 1: Identify the values given in the problem. We have a resistor with a resistance of 10 ohms and a battery with a voltage of 20 volts.
Step 2: Recall the formula for power (P) in terms of voltage (V) and resistance (R). The formula is P = V^2 / R.
Step 3: Substitute the values into the formula. Replace V with 20 volts and R with 10 ohms: P = 20^2 / 10.
Step 4: Calculate 20^2, which is 400.
Step 5: Now divide 400 by 10 to find the power: 400 / 10 = 40.
Step 6: Conclude that the power dissipated by the resistor is 40 watts.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, where V = I * R.
Power Calculation – The formula for calculating power (P) in an electrical circuit, which can be expressed as P = V^2 / R or P = I^2 * R.