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In a circuit with a 9V battery and two resistors in series (R1 = 3Ω, R2 = 6Ω), w
In a circuit with a 9V battery and two resistors in series (R1 = 3Ω, R2 = 6Ω), what is the voltage across R2?
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Practice Questions
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Q1
In a circuit with a 9V battery and two resistors in series (R1 = 3Ω, R2 = 6Ω), what is the voltage across R2?
6V
3V
9V
0V
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Using voltage division, V_R2 = (R2 / (R1 + R2)) * V_total = (6Ω / (3Ω + 6Ω)) * 9V = 6V.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with a 9V battery and two resistors in series (R1 = 3Ω, R2 = 6Ω), what is the voltage across R2?
Solution:
Using voltage division, V_R2 = (R2 / (R1 + R2)) * V_total = (6Ω / (3Ω + 6Ω)) * 9V = 6V.
Steps: 6
Show Steps
Step 1: Identify the total voltage from the battery, which is 9V.
Step 2: Identify the values of the resistors: R1 = 3Ω and R2 = 6Ω.
Step 3: Calculate the total resistance in the circuit by adding R1 and R2: Total Resistance = R1 + R2 = 3Ω + 6Ω = 9Ω.
Step 4: Use the voltage division formula to find the voltage across R2: V_R2 = (R2 / Total Resistance) * V_total.
Step 5: Substitute the values into the formula: V_R2 = (6Ω / 9Ω) * 9V.
Step 6: Simplify the calculation: V_R2 = (6 / 9) * 9V = 6V.
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