Using Kirchhoff's Current Law, if three currents enter a junction as 3A, 2A, and I, what is the value of I if the total current leaving the junction is 5A?
Practice Questions
1 question
Q1
Using Kirchhoff's Current Law, if three currents enter a junction as 3A, 2A, and I, what is the value of I if the total current leaving the junction is 5A?
4A
5A
2A
3A
According to KCL, I = Total entering - Total leaving = (3A + 2A) - 5A = 0A.
Questions & Step-by-step Solutions
1 item
Q
Q: Using Kirchhoff's Current Law, if three currents enter a junction as 3A, 2A, and I, what is the value of I if the total current leaving the junction is 5A?
Solution: According to KCL, I = Total entering - Total leaving = (3A + 2A) - 5A = 0A.
Steps: 6
Step 1: Identify the currents entering the junction. They are 3A, 2A, and I.
Step 2: Add the known currents entering the junction: 3A + 2A = 5A.
Step 3: According to Kirchhoff's Current Law (KCL), the total current entering a junction must equal the total current leaving the junction.
Step 4: The total current leaving the junction is given as 5A.
Step 5: Set up the equation: Total entering (5A) = Total leaving (5A).
Step 6: Since the total entering is already 5A, we can conclude that I must be 0A to satisfy KCL.
