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A is 3 times as old as B. If the sum of their ages is 48 years, how old is A?
A is 3 times as old as B. If the sum of their ages is 48 years, how old is A?
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Practice Questions
1 question
Q1
A is 3 times as old as B. If the sum of their ages is 48 years, how old is A?
36
24
12
18
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Let B's age be x. Then A's age is 3x. So, x + 3x = 48, which gives 4x = 48, hence x = 12. Therefore, A is 3 * 12 = 36 years old.
Questions & Step-by-step Solutions
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Q
Q: A is 3 times as old as B. If the sum of their ages is 48 years, how old is A?
Solution:
Let B's age be x. Then A's age is 3x. So, x + 3x = 48, which gives 4x = 48, hence x = 12. Therefore, A is 3 * 12 = 36 years old.
Steps: 8
Show Steps
Step 1: Let B's age be represented by the variable x.
Step 2: Since A is 3 times as old as B, we can express A's age as 3x.
Step 3: The problem states that the sum of A's age and B's age is 48 years. We can write this as x + 3x = 48.
Step 4: Combine the terms on the left side: 4x = 48.
Step 5: To find the value of x, divide both sides of the equation by 4: x = 48 / 4.
Step 6: Calculate the value: x = 12. This means B is 12 years old.
Step 7: Now, to find A's age, multiply B's age by 3: A's age = 3 * 12.
Step 8: Calculate A's age: A = 36 years old.
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