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In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω),

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Question: In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω), what is the current flowing through the circuit?

Options:

  1. 2A
  2. 1A
  3. 0.5A
  4. 3A

Correct Answer: 1A

Solution: 

Total resistance R_total = R1 + R2 = 2Ω + 3Ω = 5Ω. Current I = V / R_total = 10V / 5Ω = 2A.

In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω),

Practice Questions

Q1
In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω), what is the current flowing through the circuit?
  1. 2A
  2. 1A
  3. 0.5A
  4. 3A

Questions & Step-by-Step Solutions

In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω), what is the current flowing through the circuit?
  • Step 1: Identify the voltage of the battery, which is 10V.
  • Step 2: Identify the values of the resistors: R1 = 2Ω and R2 = 3Ω.
  • Step 3: Calculate the total resistance in the circuit by adding the resistances of R1 and R2: R_total = R1 + R2.
  • Step 4: Substitute the values: R_total = 2Ω + 3Ω = 5Ω.
  • Step 5: Use Ohm's Law to find the current: I = V / R_total.
  • Step 6: Substitute the values: I = 10V / 5Ω.
  • Step 7: Calculate the current: I = 2A.
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
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