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In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω),
In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω), what is the current flowing through the circuit?
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Practice Questions
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Q1
In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω), what is the current flowing through the circuit?
2A
1A
0.5A
3A
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Total resistance R_total = R1 + R2 = 2Ω + 3Ω = 5Ω. Current I = V / R_total = 10V / 5Ω = 2A.
Questions & Step-by-step Solutions
1 item
Q
Q: In a circuit with a 10V battery and two resistors in series (R1 = 2Ω, R2 = 3Ω), what is the current flowing through the circuit?
Solution:
Total resistance R_total = R1 + R2 = 2Ω + 3Ω = 5Ω. Current I = V / R_total = 10V / 5Ω = 2A.
Steps: 7
Show Steps
Step 1: Identify the voltage of the battery, which is 10V.
Step 2: Identify the values of the resistors: R1 = 2Ω and R2 = 3Ω.
Step 3: Calculate the total resistance in the circuit by adding the resistances of R1 and R2: R_total = R1 + R2.
Step 4: Substitute the values: R_total = 2Ω + 3Ω = 5Ω.
Step 5: Use Ohm's Law to find the current: I = V / R_total.
Step 6: Substitute the values: I = 10V / 5Ω.
Step 7: Calculate the current: I = 2A.
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