Using Kirchhoff's Voltage Law, if a loop in a circuit has a 12V battery and two

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Question: Using Kirchhoff\'s Voltage Law, if a loop in a circuit has a 12V battery and two resistors of 4Ω and 6Ω, what is the voltage across the 4Ω resistor?

Options:

4.8V
8V
6V
3.2V

Correct Answer: 8V

Solution:

Using voltage division, V_R1 = (R1 / (R1 + R2)) * V_total = (4Ω / (4Ω + 6Ω)) * 12V = 4.8V.

Using Kirchhoff's Voltage Law, if a loop in a circuit has a 12V battery and two

Practice Questions

Using Kirchhoff's Voltage Law, if a loop in a circuit has a 12V battery and two resistors of 4Ω and 6Ω, what is the voltage across the 4Ω resistor?

4.8V
8V
6V
3.2V

Questions & Step-by-Step Solutions

Using Kirchhoff's Voltage Law, if a loop in a circuit has a 12V battery and two resistors of 4Ω and 6Ω, what is the voltage across the 4Ω resistor?

Step 1: Identify the total voltage in the circuit, which is given as 12V from the battery.
Step 2: Identify the resistors in the circuit. We have R1 = 4Ω and R2 = 6Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors: R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.
Step 4: Use the voltage division formula to find the voltage across the 4Ω resistor (R1). The formula is V_R1 = (R1 / R_total) * V_total.
Step 5: Substitute the values into the formula: V_R1 = (4Ω / 10Ω) * 12V.
Step 6: Calculate the voltage across the 4Ω resistor: V_R1 = 0.4 * 12V = 4.8V.

Kirchhoff's Voltage Law – This law states that the sum of the electrical potential differences (voltage) around any closed network is zero.
Voltage Division – A technique used to determine the voltage drop across individual resistors in a series circuit based on their resistance values.

Using Kirchhoff's Voltage Law, if a loop in a circuit has a 12V battery and two

What’s inside this PDF?

Using Kirchhoff's Voltage Law, if a loop in a circuit has a 12V battery and two

Practice Questions

Questions & Step-by-Step Solutions

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