In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?

Practice Questions

1 question
Q1
In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?
  1. 10Ω

Questions & Step-by-step Solutions

1 item
Q
Q: In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?
Solution: Total resistance in series is R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.
Steps: 5

Related Questions

Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely