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In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω

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Question: In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?

Options:

  1. 5Ω
  2. 10Ω
  3. 8Ω
  4. 3Ω

Correct Answer: 10Ω

Solution: 

Total resistance in series is R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.

In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω

Practice Questions

Q1
In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?
  1. 5Ω
  2. 10Ω
  3. 8Ω
  4. 3Ω

Questions & Step-by-Step Solutions

In a circuit with three resistors R1, R2, and R3 connected in series, if R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω, what is the total resistance?
  • Step 1: Identify the values of the resistors. R1 = 2Ω, R2 = 3Ω, R3 = 5Ω.
  • Step 2: Write down the formula for total resistance in a series circuit, which is R_total = R1 + R2 + R3.
  • Step 3: Substitute the values of the resistors into the formula: R_total = 2Ω + 3Ω + 5Ω.
  • Step 4: Perform the addition: 2 + 3 = 5, then 5 + 5 = 10.
  • Step 5: Conclude that the total resistance is R_total = 10Ω.
  • Series Circuit Resistance – In a series circuit, the total resistance is the sum of the individual resistances.
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