What is the total resistance of a circuit with a 3Ω and a 5Ω resistor in series?

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Question: What is the total resistance of a circuit with a 3Ω and a 5Ω resistor in series?

Options:

Correct Answer: 8Ω

Solution:

Total resistance R = R1 + R2 = 3Ω + 5Ω = 8Ω.

What is the total resistance of a circuit with a 3Ω and a 5Ω resistor in series?

What is the total resistance of a circuit with a 3Ω and a 5Ω resistor in series?

Step 1: Identify the resistors in the circuit. We have a 3Ω resistor and a 5Ω resistor.
Step 2: Understand that when resistors are in series, you add their resistances together.
Step 3: Write down the formula for total resistance in series: Total resistance R = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R = 3Ω + 5Ω.
Step 5: Perform the addition: 3Ω + 5Ω = 8Ω.
Step 6: Conclude that the total resistance of the circuit is 8Ω.

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