A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery

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Question: A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?

Options:

Correct Answer: 2A

Solution:

Total resistance R = 10Ω + 5Ω = 15Ω. Current I = V/R = 15V/15Ω = 1A.

A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?

A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?

Step 1: Identify the resistors in the circuit. We have a 10Ω resistor and a 5Ω resistor.
Step 2: Since the resistors are in series, add their resistances together. Calculate: 10Ω + 5Ω = 15Ω.
Step 3: Identify the voltage of the battery. The battery provides 15V.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 15V / 15Ω.
Step 6: Calculate the current: 15V / 15Ω = 1A.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.