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A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery
A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?
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Q1
A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?
1A
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Total resistance R = 10Ω + 5Ω = 15Ω. Current I = V/R = 15V/15Ω = 1A.
Questions & Step-by-step Solutions
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Q
Q: A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?
Solution:
Total resistance R = 10Ω + 5Ω = 15Ω. Current I = V/R = 15V/15Ω = 1A.
Steps: 6
Show Steps
Step 1: Identify the resistors in the circuit. We have a 10Ω resistor and a 5Ω resistor.
Step 2: Since the resistors are in series, add their resistances together. Calculate: 10Ω + 5Ω = 15Ω.
Step 3: Identify the voltage of the battery. The battery provides 15V.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 15V / 15Ω.
Step 6: Calculate the current: 15V / 15Ω = 1A.
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