A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery

Practice Questions

Q1
A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?
  1. 1A
  2. 2A
  3. 3A
  4. 4A

Questions & Step-by-Step Solutions

A circuit contains a 10Ω resistor and a 5Ω resistor in series with a 15V battery. What is the total current in the circuit?
  • Step 1: Identify the resistors in the circuit. We have a 10Ω resistor and a 5Ω resistor.
  • Step 2: Since the resistors are in series, add their resistances together. Calculate: 10Ω + 5Ω = 15Ω.
  • Step 3: Identify the voltage of the battery. The battery provides 15V.
  • Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
  • Step 5: Substitute the values into the formula: I = 15V / 15Ω.
  • Step 6: Calculate the current: 15V / 15Ω = 1A.
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
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