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What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected
What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in series?
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Practice Questions
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Q1
What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in series?
11Ω
10Ω
9Ω
12Ω
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In series, R_eq = R1 + R2 + R3 = 2 + 3 + 6 = 11Ω.
Questions & Step-by-step Solutions
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Q
Q: What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in series?
Solution:
In series, R_eq = R1 + R2 + R3 = 2 + 3 + 6 = 11Ω.
Steps: 6
Show Steps
Step 1: Identify the resistors and their values. We have three resistors: R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω.
Step 2: Understand that when resistors are connected in series, the total or equivalent resistance (R_eq) is the sum of all individual resistances.
Step 3: Write the formula for equivalent resistance in series: R_eq = R1 + R2 + R3.
Step 4: Substitute the values of the resistors into the formula: R_eq = 2Ω + 3Ω + 6Ω.
Step 5: Perform the addition: 2 + 3 = 5, then 5 + 6 = 11.
Step 6: Conclude that the equivalent resistance of the three resistors in series is 11Ω.
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