What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected

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Question: What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in series?

Options:

Correct Answer: 11Ω

Solution:

In series, R_eq = R1 + R2 + R3 = 2 + 3 + 6 = 11Ω.

What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in series?

What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in series?

Step 1: Identify the resistors and their values. We have three resistors: R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω.
Step 2: Understand that when resistors are connected in series, the total or equivalent resistance (R_eq) is the sum of all individual resistances.
Step 3: Write the formula for equivalent resistance in series: R_eq = R1 + R2 + R3.
Step 4: Substitute the values of the resistors into the formula: R_eq = 2Ω + 3Ω + 6Ω.
Step 5: Perform the addition: 2 + 3 = 5, then 5 + 6 = 11.
Step 6: Conclude that the equivalent resistance of the three resistors in series is 11Ω.

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