The age of I is three times the age of J. If the difference in their ages is 24

₹0.0

Question: The age of I is three times the age of J. If the difference in their ages is 24 years, how old is J?

Options:

Correct Answer: 16

Solution:

Let J\'s age be x. Then I\'s age is 3x. The difference is 3x - x = 24, hence 2x = 24, x = 12. Therefore, J is 12 years old.

The age of I is three times the age of J. If the difference in their ages is 24 years, how old is J?

The age of I is three times the age of J. If the difference in their ages is 24 years, how old is J?

Correct Answer: 12

Step 1: Let J's age be represented by the variable x.
Step 2: Since I's age is three times J's age, we can express I's age as 3x.
Step 3: The problem states that the difference in their ages is 24 years. We can write this as an equation: 3x - x = 24.
Step 4: Simplify the equation: 3x - x equals 2x, so we have 2x = 24.
Step 5: To find the value of x, divide both sides of the equation by 2: x = 24 / 2.
Step 6: Calculate the result: x = 12.
Step 7: Since x represents J's age, J is 12 years old.

Algebraic Expressions – The question tests the ability to set up and solve equations based on relationships between variables.
Age Problems – It specifically focuses on solving age-related problems using algebra.