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The age of I is three times the age of J. If the difference in their ages is 24
The age of I is three times the age of J. If the difference in their ages is 24 years, how old is J?
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Practice Questions
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Q1
The age of I is three times the age of J. If the difference in their ages is 24 years, how old is J?
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Let J's age be x. Then I's age is 3x. The difference is 3x - x = 24, hence 2x = 24, x = 12. Therefore, J is 12 years old.
Questions & Step-by-step Solutions
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Q
Q: The age of I is three times the age of J. If the difference in their ages is 24 years, how old is J?
Solution:
Let J's age be x. Then I's age is 3x. The difference is 3x - x = 24, hence 2x = 24, x = 12. Therefore, J is 12 years old.
Steps: 7
Show Steps
Step 1: Let J's age be represented by the variable x.
Step 2: Since I's age is three times J's age, we can express I's age as 3x.
Step 3: The problem states that the difference in their ages is 24 years. We can write this as an equation: 3x - x = 24.
Step 4: Simplify the equation: 3x - x equals 2x, so we have 2x = 24.
Step 5: To find the value of x, divide both sides of the equation by 2: x = 24 / 2.
Step 6: Calculate the result: x = 12.
Step 7: Since x represents J's age, J is 12 years old.
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