A's age is 2 years more than B's age. If the sum of their ages is 34, what is A's age?
Practice Questions
1 question
Q1
A's age is 2 years more than B's age. If the sum of their ages is 34, what is A's age?
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Let B's age be x. Then A's age is x + 2. So, x + (x + 2) = 34, which gives 2x + 2 = 34, hence 2x = 32, x = 16. Therefore, A's age is 16 + 2 = 18.
Questions & Step-by-step Solutions
1 item
Q
Q: A's age is 2 years more than B's age. If the sum of their ages is 34, what is A's age?
Solution: Let B's age be x. Then A's age is x + 2. So, x + (x + 2) = 34, which gives 2x + 2 = 34, hence 2x = 32, x = 16. Therefore, A's age is 16 + 2 = 18.
Steps: 7
Step 1: Let B's age be represented by the variable x.
Step 2: Since A's age is 2 years more than B's age, we can express A's age as x + 2.
Step 3: The problem states that the sum of A's age and B's age is 34. We can write this as an equation: x + (x + 2) = 34.
Step 4: Simplify the equation: Combine like terms to get 2x + 2 = 34.
Step 5: To isolate the variable, subtract 2 from both sides of the equation: 2x = 34 - 2, which simplifies to 2x = 32.
Step 6: Now, divide both sides by 2 to solve for x: x = 32 / 2, which gives x = 16.
Step 7: Since x represents B's age, we find A's age by adding 2: A's age = x + 2 = 16 + 2, which equals 18.
