Three years ago, A was 2 times as old as B. If B is currently 12 years old, how

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Question: Three years ago, A was 2 times as old as B. If B is currently 12 years old, how old is A now?

Options:

Correct Answer: 20

Solution:

Three years ago, B was 12 - 3 = 9 years old. A was 2 * 9 = 18 years old. Now, A is 18 + 3 = 21 years old.

Three years ago, A was 2 times as old as B. If B is currently 12 years old, how old is A now?

Three years ago, A was 2 times as old as B. If B is currently 12 years old, how old is A now?

Correct Answer: 21

Step 1: Determine B's age three years ago. Since B is currently 12 years old, we calculate B's age three years ago by subtracting 3 from 12. So, 12 - 3 = 9 years old.
Step 2: Find A's age three years ago. The problem states that three years ago, A was 2 times as old as B. Since we found B's age three years ago to be 9, we calculate A's age by multiplying 9 by 2. So, 2 * 9 = 18 years old.
Step 3: Calculate A's current age. Since A was 18 years old three years ago, we need to add 3 years to find A's current age. So, 18 + 3 = 21 years old.

Age Relationships – Understanding how to relate the ages of two individuals over time.
Basic Arithmetic – Performing simple calculations involving addition and multiplication.
Time Adjustment – Adjusting ages based on a specified time frame in the past.