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Evaluate ∫_0^1 (x^3 + 2x^2) dx.
Evaluate ∫_0^1 (x^3 + 2x^2) dx.
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Practice Questions
1 question
Q1
Evaluate ∫_0^1 (x^3 + 2x^2) dx.
1/4
1/3
1/2
1
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∫_0^1 (x^3 + 2x^2) dx = [x^4/4 + 2x^3/3] from 0 to 1 = (1/4 + 2/3) = 11/12.
Questions & Step-by-step Solutions
1 item
Q
Q: Evaluate ∫_0^1 (x^3 + 2x^2) dx.
Solution:
∫_0^1 (x^3 + 2x^2) dx = [x^4/4 + 2x^3/3] from 0 to 1 = (1/4 + 2/3) = 11/12.
Steps: 10
Show Steps
Step 1: Identify the integral to evaluate: ∫_0^1 (x^3 + 2x^2) dx.
Step 2: Break down the integral into two parts: ∫_0^1 x^3 dx + ∫_0^1 2x^2 dx.
Step 3: Find the antiderivative of x^3, which is (x^4)/4.
Step 4: Find the antiderivative of 2x^2, which is (2x^3)/3.
Step 5: Combine the antiderivatives: (x^4)/4 + (2x^3)/3.
Step 6: Evaluate the combined antiderivative from 0 to 1: [(1^4)/4 + (2*1^3)/3] - [(0^4)/4 + (2*0^3)/3].
Step 7: Calculate the values: (1/4 + 2/3).
Step 8: Find a common denominator to add 1/4 and 2/3, which is 12.
Step 9: Convert 1/4 to 3/12 and 2/3 to 8/12.
Step 10: Add the fractions: 3/12 + 8/12 = 11/12.
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