If f(x) = { x^2 + 1, x < 0; k, x = 0; 2x + 1, x > 0 }, what value of k mak

Practice Questions

Q1
If f(x) = { x^2 + 1, x < 0; k, x = 0; 2x + 1, x > 0 }, what value of k makes f continuous at x = 0?
  1. 0
  2. 1
  3. 2
  4. 3

Questions & Step-by-Step Solutions

If f(x) = { x^2 + 1, x < 0; k, x = 0; 2x + 1, x > 0 }, what value of k makes f continuous at x = 0?
  • Step 1: Understand that f(x) is a piecewise function, which means it has different expressions for different values of x.
  • Step 2: Identify the three parts of the function: f(x) = x^2 + 1 when x < 0, f(x) = k when x = 0, and f(x) = 2x + 1 when x > 0.
  • Step 3: To find the value of k that makes f continuous at x = 0, we need to ensure that the left-hand limit (as x approaches 0 from the left) equals the right-hand limit (as x approaches 0 from the right) and also equals f(0).
  • Step 4: Calculate the left-hand limit: as x approaches 0 from the left (x < 0), use the expression x^2 + 1. So, limit as x approaches 0 from the left is 0^2 + 1 = 1.
  • Step 5: Calculate the right-hand limit: as x approaches 0 from the right (x > 0), use the expression 2x + 1. So, limit as x approaches 0 from the right is 2(0) + 1 = 1.
  • Step 6: Since both limits (from the left and right) equal 1, for f(x) to be continuous at x = 0, we need k to also equal 1.
  • Step 7: Therefore, the value of k that makes f continuous at x = 0 is k = 1.
  • Piecewise Functions – Understanding how piecewise functions behave at transition points.
  • Limits – Calculating limits from both sides to determine continuity.
  • Continuity – The condition for a function to be continuous at a point.
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