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If the equation 2x^2 + 3x - 5 = 0 has roots r1 and r2, what is the value of r1 +
If the equation 2x^2 + 3x - 5 = 0 has roots r1 and r2, what is the value of r1 + r2?
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Q1
If the equation 2x^2 + 3x - 5 = 0 has roots r1 and r2, what is the value of r1 + r2?
-3/2
3/2
5/2
-5/2
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Using Vieta's formulas, r1 + r2 = -b/a = -3/2.
Questions & Step-by-step Solutions
1 item
Q
Q: If the equation 2x^2 + 3x - 5 = 0 has roots r1 and r2, what is the value of r1 + r2?
Solution:
Using Vieta's formulas, r1 + r2 = -b/a = -3/2.
Steps: 5
Show Steps
Step 1: Identify the coefficients in the equation 2x^2 + 3x - 5 = 0. Here, a = 2, b = 3, and c = -5.
Step 2: Recall Vieta's formulas, which relate the coefficients of a polynomial to sums and products of its roots.
Step 3: According to Vieta's formulas, the sum of the roots (r1 + r2) is given by the formula -b/a.
Step 4: Substitute the values of b and a into the formula: r1 + r2 = -3/2.
Step 5: Simplify the expression to find the value of r1 + r2.
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