What is the standard enthalpy change for the reaction 2H2(g) + O2(g) → 2H2O(l)?

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Question: What is the standard enthalpy change for the reaction 2H2(g) + O2(g) → 2H2O(l)?

Options:

Correct Answer: -241.82 kJ/mol

Solution:

The standard enthalpy of formation of water is -241.82 kJ/mol.

What is the standard enthalpy change for the reaction 2H2(g) + O2(g) → 2H2O(l)?

What is the standard enthalpy change for the reaction 2H2(g) + O2(g) → 2H2O(l)?

Step 1: Identify the reaction you are looking at, which is 2H2(g) + O2(g) → 2H2O(l).
Step 2: Understand that the standard enthalpy change for a reaction can be found using the standard enthalpy of formation values.
Step 3: Look up the standard enthalpy of formation for water (H2O). It is -241.82 kJ/mol.
Step 4: Since the reaction produces 2 moles of water, multiply the standard enthalpy of formation of water by 2.
Step 5: Calculate: 2 * (-241.82 kJ/mol) = -483.64 kJ.
Step 6: The standard enthalpy change for the reaction 2H2(g) + O2(g) → 2H2O(l) is -483.64 kJ.

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