In an isothermal process, the temperature of the system remains constant. What is the work done by the gas during expansion?
Practice Questions
1 question
Q1
In an isothermal process, the temperature of the system remains constant. What is the work done by the gas during expansion?
Zero
nRT ln(Vf/Vi)
nRT (Vf - Vi)
nR (Tf - Ti)
In an isothermal process, the work done by the gas is given by W = nRT ln(Vf/Vi).
Questions & Step-by-step Solutions
1 item
Q
Q: In an isothermal process, the temperature of the system remains constant. What is the work done by the gas during expansion?
Solution: In an isothermal process, the work done by the gas is given by W = nRT ln(Vf/Vi).
Steps: 6
Step 1: Understand that an isothermal process means the temperature of the gas does not change.
Step 2: Identify the variables: 'n' is the number of moles of gas, 'R' is the ideal gas constant, 'T' is the temperature in Kelvin, 'Vi' is the initial volume, and 'Vf' is the final volume.
Step 3: Recall the formula for work done by the gas during expansion in an isothermal process: W = nRT ln(Vf/Vi).
Step 4: Plug in the values for n, R, T, Vf, and Vi into the formula to calculate the work done.
Step 5: Calculate the natural logarithm of the ratio of final volume to initial volume, ln(Vf/Vi).
Step 6: Multiply n, R, T, and the result from Step 5 to find the total work done by the gas.
