In an isothermal process, the temperature of the system remains constant. What i

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Question: In an isothermal process, the temperature of the system remains constant. What is the work done by the gas during expansion?

Options:

Correct Answer: nRT ln(Vf/Vi)

Solution:

In an isothermal process, the work done by the gas is given by W = nRT ln(Vf/Vi).

In an isothermal process, the temperature of the system remains constant. What is the work done by the gas during expansion?

In an isothermal process, the temperature of the system remains constant. What is the work done by the gas during expansion?

Step 1: Understand that an isothermal process means the temperature of the gas does not change.
Step 2: Identify the variables: 'n' is the number of moles of gas, 'R' is the ideal gas constant, 'T' is the temperature in Kelvin, 'Vi' is the initial volume, and 'Vf' is the final volume.
Step 3: Recall the formula for work done by the gas during expansion in an isothermal process: W = nRT ln(Vf/Vi).
Step 4: Plug in the values for n, R, T, Vf, and Vi into the formula to calculate the work done.
Step 5: Calculate the natural logarithm of the ratio of final volume to initial volume, ln(Vf/Vi).
Step 6: Multiply n, R, T, and the result from Step 5 to find the total work done by the gas.

Isothermal Process – An isothermal process is a thermodynamic process in which the temperature of the system remains constant throughout the process.
Work Done by Gas – The work done by a gas during expansion in an isothermal process can be calculated using the formula W = nRT ln(Vf/Vi), where n is the number of moles, R is the ideal gas constant, T is the temperature, Vf is the final volume, and Vi is the initial volume.