A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at ran

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Question: A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is not green?

Options:

Correct Answer: 4/5

Solution:

The total number of marbles is 5 + 3 + 2 = 10. The number of non-green marbles is 5 + 2 = 7. The probability is 7/10 = 7/10.

A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is not green?

A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is not green?

Correct Answer: 7/10

Step 1: Count the total number of marbles in the jar. There are 5 red, 3 green, and 2 blue marbles.
Step 2: Add the number of marbles together: 5 (red) + 3 (green) + 2 (blue) = 10 total marbles.
Step 3: Identify the number of non-green marbles. Non-green marbles are red and blue, so add them: 5 (red) + 2 (blue) = 7 non-green marbles.
Step 4: Calculate the probability of drawing a non-green marble. The probability is the number of non-green marbles divided by the total number of marbles: 7 (non-green) / 10 (total) = 7/10.

Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Counting Outcomes – Understanding how to count the total number of items and categorize them based on specific criteria.