A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at ran
Practice Questions
Q1
A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is not green?
1/5
2/5
4/5
3/5
Questions & Step-by-Step Solutions
A jar contains 5 red, 3 green, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is not green?
Correct Answer: 7/10
Step 1: Count the total number of marbles in the jar. There are 5 red, 3 green, and 2 blue marbles.
Step 2: Add the number of marbles together: 5 (red) + 3 (green) + 2 (blue) = 10 total marbles.
Step 3: Identify the number of non-green marbles. Non-green marbles are red and blue, so add them: 5 (red) + 2 (blue) = 7 non-green marbles.
Step 4: Calculate the probability of drawing a non-green marble. The probability is the number of non-green marbles divided by the total number of marbles: 7 (non-green) / 10 (total) = 7/10.
Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Counting Outcomes – Understanding how to count the total number of items and categorize them based on specific criteria.
