If the vapor pressure of a solution is 80 mmHg and the vapor pressure of the pure solvent is 120 mmHg, what is the mole fraction of the solvent in the solution?
Practice Questions
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Q1
If the vapor pressure of a solution is 80 mmHg and the vapor pressure of the pure solvent is 120 mmHg, what is the mole fraction of the solvent in the solution?
Q: If the vapor pressure of a solution is 80 mmHg and the vapor pressure of the pure solvent is 120 mmHg, what is the mole fraction of the solvent in the solution?
Step 1: Understand that the vapor pressure of a solution is given as 80 mmHg.
Step 2: Know that the vapor pressure of the pure solvent is 120 mmHg.
Step 3: Recall Raoult's Law, which states that the vapor pressure of the solution (P_solution) equals the mole fraction of the solvent (X_solvent) multiplied by the vapor pressure of the pure solvent (P_solvent).
Step 4: Write the equation from Raoult's Law: P_solution = X_solvent * P_solvent.
Step 5: Substitute the known values into the equation: 80 mmHg = X_solvent * 120 mmHg.
Step 6: To find X_solvent, rearrange the equation: X_solvent = P_solution / P_solvent.
