If the vapor pressure of a solution is 80 mmHg and the vapor pressure of the pur
Practice Questions
Q1
If the vapor pressure of a solution is 80 mmHg and the vapor pressure of the pure solvent is 120 mmHg, what is the mole fraction of the solvent in the solution?
0.67
0.33
0.50
0.75
Questions & Step-by-Step Solutions
If the vapor pressure of a solution is 80 mmHg and the vapor pressure of the pure solvent is 120 mmHg, what is the mole fraction of the solvent in the solution?
Step 1: Understand that the vapor pressure of a solution is given as 80 mmHg.
Step 2: Know that the vapor pressure of the pure solvent is 120 mmHg.
Step 3: Recall Raoult's Law, which states that the vapor pressure of the solution (P_solution) equals the mole fraction of the solvent (X_solvent) multiplied by the vapor pressure of the pure solvent (P_solvent).
Step 4: Write the equation from Raoult's Law: P_solution = X_solvent * P_solvent.
Step 5: Substitute the known values into the equation: 80 mmHg = X_solvent * 120 mmHg.
Step 6: To find X_solvent, rearrange the equation: X_solvent = P_solution / P_solvent.
