A solution has a density of 1.2 g/mL and contains 10% (w/v) NaOH. What is the ma

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Question: A solution has a density of 1.2 g/mL and contains 10% (w/v) NaOH. What is the mass of NaOH in 1 L of this solution?

Options:

Correct Answer: 120 g

Solution:

Mass of NaOH = (10/100) x 1000 mL = 100 g.

A solution has a density of 1.2 g/mL and contains 10% (w/v) NaOH. What is the mass of NaOH in 1 L of this solution?

A solution has a density of 1.2 g/mL and contains 10% (w/v) NaOH. What is the mass of NaOH in 1 L of this solution?

Step 1: Understand that '10% (w/v) NaOH' means there are 10 grams of NaOH in every 100 mL of solution.
Step 2: Since we want to find the mass of NaOH in 1 L (which is 1000 mL), we need to calculate how many grams are in that volume.
Step 3: Use the formula: Mass of NaOH = (percentage/100) x volume in mL.
Step 4: Plug in the values: Mass of NaOH = (10/100) x 1000 mL.
Step 5: Calculate: (10/100) x 1000 = 100 grams.
Step 6: Therefore, the mass of NaOH in 1 L of the solution is 100 grams.

Density and Concentration Calculations – Understanding how to calculate mass from volume and concentration (w/v) in a solution.
Weight/Volume Percent (w/v) – Interpreting the meaning of a 10% (w/v) solution, which indicates grams of solute per 100 mL of solution.