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What is the molality of a solution prepared by dissolving 3 moles of KCl in 1 kg
What is the molality of a solution prepared by dissolving 3 moles of KCl in 1 kg of water?
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Q1
What is the molality of a solution prepared by dissolving 3 moles of KCl in 1 kg of water?
3 m
1.5 m
2 m
4 m
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Molality (m) = moles of solute / kg of solvent = 3 moles / 1 kg = 3 m.
Questions & Step-by-step Solutions
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Q
Q: What is the molality of a solution prepared by dissolving 3 moles of KCl in 1 kg of water?
Solution:
Molality (m) = moles of solute / kg of solvent = 3 moles / 1 kg = 3 m.
Steps: 6
Show Steps
Step 1: Identify the amount of solute (KCl) in moles. In this case, we have 3 moles of KCl.
Step 2: Identify the amount of solvent (water) in kilograms. Here, we have 1 kg of water.
Step 3: Use the formula for molality, which is molality (m) = moles of solute / kg of solvent.
Step 4: Plug in the values into the formula: m = 3 moles / 1 kg.
Step 5: Calculate the result: 3 moles / 1 kg = 3.
Step 6: State the final answer: The molality of the solution is 3 m.
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