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If the osmotic pressure of a solution is 3.0 atm at 25 °C, what is the molarity
If the osmotic pressure of a solution is 3.0 atm at 25 °C, what is the molarity of the solution? (R = 0.0821 L atm/(K mol))
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Practice Questions
1 question
Q1
If the osmotic pressure of a solution is 3.0 atm at 25 °C, what is the molarity of the solution? (R = 0.0821 L atm/(K mol))
0.12 M
0.15 M
0.18 M
0.20 M
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Molarity = π / (RT) = 3.0 / (0.0821 * 298) = 0.12 M
Questions & Step-by-step Solutions
1 item
Q
Q: If the osmotic pressure of a solution is 3.0 atm at 25 °C, what is the molarity of the solution? (R = 0.0821 L atm/(K mol))
Solution:
Molarity = π / (RT) = 3.0 / (0.0821 * 298) = 0.12 M
Steps: 7
Show Steps
Step 1: Identify the formula for molarity (M) using osmotic pressure (π): M = π / (RT).
Step 2: Note the values given in the question: π = 3.0 atm, R = 0.0821 L atm/(K mol), and the temperature (T) = 25 °C.
Step 3: Convert the temperature from Celsius to Kelvin: T = 25 + 273 = 298 K.
Step 4: Substitute the values into the formula: M = 3.0 / (0.0821 * 298).
Step 5: Calculate the denominator: 0.0821 * 298 = 24.4758.
Step 6: Divide the osmotic pressure by the calculated value: M = 3.0 / 24.4758.
Step 7: Perform the division to find the molarity: M ≈ 0.12 M.
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