Calculate the molality of a solution if the boiling point elevation is 1.024 °C. (K_b for water = 0.512 °C kg/mol)

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Q: Calculate the molality of a solution if the boiling point elevation is 1.024 °C. (K_b for water = 0.512 °C kg/mol)

Solution: Molality = ΔT_b / (i * K_b) = 1.024 / (2 * 0.512) = 1 mol/kg

Steps: 7

Step 1: Understand the formula for molality (m) in relation to boiling point elevation: m = ΔT_b / (i * K_b).
Step 2: Identify the values given in the problem: ΔT_b (boiling point elevation) is 1.024 °C, and K_b (boiling point constant for water) is 0.512 °C kg/mol.
Step 3: Determine the van 't Hoff factor (i). For this example, we will assume the solute is a non-electrolyte that dissociates into 2 particles, so i = 2.
Step 4: Substitute the values into the formula: m = 1.024 / (2 * 0.512).
Step 5: Calculate the denominator: 2 * 0.512 = 1.024.
Step 6: Divide the boiling point elevation by the calculated denominator: 1.024 / 1.024 = 1.
Step 7: Conclude that the molality of the solution is 1 mol/kg.