What is the reducing agent in the reaction 2MnO4- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10

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Question: What is the reducing agent in the reaction 2MnO4- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O?

Options:

Correct Answer: C2O4^2-

Solution:

C2O4^2- is the reducing agent as it donates electrons.

What is the reducing agent in the reaction 2MnO4- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O?

What is the reducing agent in the reaction 2MnO4- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O?

Step 1: Identify the reactants in the reaction. The reactants are 2MnO4-, 5C2O4^2-, and 6H+.
Step 2: Understand what a reducing agent is. A reducing agent is a substance that donates electrons to another substance.
Step 3: Look at the oxidation states of the elements in the reactants. In C2O4^2-, carbon has an oxidation state of +3.
Step 4: Determine what happens to C2O4^2- in the reaction. It gets converted to CO2, where carbon has an oxidation state of +4.
Step 5: Since the oxidation state of carbon increases from +3 to +4, C2O4^2- loses electrons.
Step 6: Conclude that C2O4^2- is the reducing agent because it donates electrons during the reaction.

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