What is the pH of a 0.05 M solution of sulfuric acid (H2SO4)?
Practice Questions
1 question
Q1
What is the pH of a 0.05 M solution of sulfuric acid (H2SO4)?
1
1.3
1.7
2
H2SO4 is a strong acid and dissociates completely; [H+] = 0.05 M, so pH = -log(0.05) ≈ 1.3
Questions & Step-by-step Solutions
1 item
Q
Q: What is the pH of a 0.05 M solution of sulfuric acid (H2SO4)?
Solution: H2SO4 is a strong acid and dissociates completely; [H+] = 0.05 M, so pH = -log(0.05) ≈ 1.3
Steps: 6
Step 1: Identify the concentration of the sulfuric acid solution, which is 0.05 M.
Step 2: Recognize that sulfuric acid (H2SO4) is a strong acid, meaning it dissociates completely in water.
Step 3: Since H2SO4 dissociates completely, the concentration of hydrogen ions [H+] in the solution is equal to the concentration of the acid, which is 0.05 M.
Step 4: Use the formula for pH, which is pH = -log[H+].
Step 5: Substitute the value of [H+] into the formula: pH = -log(0.05).
