If 50 mL of 0.1 M HCl is mixed with 50 mL of 0.1 M NaOH, what is the resulting p

If 50 mL of 0.1 M HCl is mixed with 50 mL of 0.1 M NaOH, what is the resulting pH?

If 50 mL of 0.1 M HCl is mixed with 50 mL of 0.1 M NaOH, what is the resulting pH?

Step 1: Identify the substances being mixed. We have 50 mL of 0.1 M HCl (hydrochloric acid) and 50 mL of 0.1 M NaOH (sodium hydroxide).
Step 2: Understand that HCl is an acid and NaOH is a base.
Step 3: When an acid (HCl) and a base (NaOH) are mixed, they undergo a chemical reaction called neutralization.
Step 4: In this reaction, HCl donates protons (H+) and NaOH donates hydroxide ions (OH-).
Step 5: The H+ ions from HCl react with the OH- ions from NaOH to form water (H2O).
Step 6: Since both HCl and NaOH are present in equal amounts (50 mL of each), they completely neutralize each other.
Step 7: The resulting solution contains only water and any remaining ions, but in this case, there are none left over.
Step 8: A solution that is neutral (neither acidic nor basic) has a pH of 7.

Neutralization Reaction – The reaction between an acid (HCl) and a base (NaOH) to form water and a salt, resulting in a neutral solution.
pH Calculation – Understanding that the pH of a neutral solution at 25°C is 7.
Concentration and Volume – Recognizing that equal concentrations and volumes of a strong acid and strong base will neutralize each other.