In a reaction A → B, if the rate of formation of B is 0.5 mol/L·s, what is the rate of disappearance of A?

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Q: In a reaction A → B, if the rate of formation of B is 0.5 mol/L·s, what is the rate of disappearance of A?

Solution: For the reaction A → B, the rate of disappearance of A is equal to the rate of formation of B, thus it is 1.0 mol/L·s.

Steps: 7

Step 1: Understand the reaction A → B. This means that substance A is turning into substance B.
Step 2: Note that the rate of formation of B is given as 0.5 mol/L·s. This means B is being produced at this rate.
Step 3: In a chemical reaction, the rate of disappearance of the reactant (A) is related to the rate of formation of the product (B).
Step 4: For every 1 mole of B that is formed, 1 mole of A disappears. Therefore, the rate of disappearance of A is equal to the rate of formation of B.
Step 5: Since the rate of formation of B is 0.5 mol/L·s, the rate of disappearance of A is also 0.5 mol/L·s.
Step 6: However, since we are looking for the rate of disappearance of A in terms of the stoichiometry of the reaction, we multiply the rate of formation of B by 2 (because for every 1 mole of B formed, 1 mole of A disappears).
Step 7: Therefore, the rate of disappearance of A is 1.0 mol/L·s.