What is the shape of the molecule SF6 according to VSEPR theory?
Practice Questions
Q1
What is the shape of the molecule SF6 according to VSEPR theory?
Square planar
Octahedral
Trigonal bipyramidal
Tetrahedral
Questions & Step-by-Step Solutions
What is the shape of the molecule SF6 according to VSEPR theory?
Step 1: Identify the molecule SF6, which consists of one sulfur (S) atom and six fluorine (F) atoms.
Step 2: Count the number of bonding pairs. In SF6, sulfur forms six bonds with six fluorine atoms, so there are six bonding pairs.
Step 3: Check for lone pairs on the central atom (sulfur). In SF6, there are no lone pairs on the sulfur atom.
Step 4: Use VSEPR theory, which states that the shape of a molecule is determined by the number of bonding pairs and lone pairs around the central atom.
Step 5: Since there are six bonding pairs and no lone pairs, the shape of the molecule is octahedral.
