What is the mass of KCl produced when 10 g of K reacts with excess Cl2?
Practice Questions
Q1
What is the mass of KCl produced when 10 g of K reacts with excess Cl2?
74.5 g
10 g
20 g
30 g
Questions & Step-by-Step Solutions
What is the mass of KCl produced when 10 g of K reacts with excess Cl2?
Step 1: Determine the molar mass of potassium (K). The molar mass of K is approximately 39 g/mol.
Step 2: Calculate the number of moles of K in 10 g. Use the formula: moles = mass (g) / molar mass (g/mol). So, moles of K = 10 g / 39 g/mol = 0.2564 moles (approximately 0.25 moles).
Step 3: Write the balanced chemical equation for the reaction: K + Cl2 → KCl. This shows that 1 mole of K produces 1 mole of KCl.
Step 4: Since we have 0.25 moles of K, we will also produce 0.25 moles of KCl.
Step 5: Determine the molar mass of KCl. The molar mass of KCl is approximately 39 g/mol (K) + 35.5 g/mol (Cl) = 74.5 g/mol.
Step 6: Calculate the mass of KCl produced using the formula: mass = moles × molar mass. So, mass of KCl = 0.25 moles × 74.5 g/mol = 18.625 g.
