In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced fro

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Question: In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 4 grams of Fe?

Options:

Correct Answer: 20 g

Solution:

4 g of Fe = 0.071 moles. 0.071 moles of Fe produce 0.071 * 2 = 0.142 moles of FeCl3 = 0.142 * 162.5 g = 23 g.

In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 4 grams of Fe?

In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 4 grams of Fe?

Step 1: Calculate the number of moles of Fe in 4 grams. Use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of Fe is approximately 55.85 g/mol.
Step 2: Substitute the values into the formula: moles of Fe = 4 g / 55.85 g/mol.
Step 3: Perform the calculation to find the number of moles of Fe. This gives you approximately 0.071 moles of Fe.
Step 4: Use the balanced chemical equation 2Fe + 3Cl2 → 2FeCl3 to find the mole ratio. From the equation, 2 moles of Fe produce 2 moles of FeCl3.
Step 5: Since 0.071 moles of Fe are available, it will produce the same amount of FeCl3: 0.071 moles of Fe will produce 0.071 moles of FeCl3.
Step 6: Calculate the mass of FeCl3 produced. First, find the molar mass of FeCl3, which is approximately 162.5 g/mol.
Step 7: Use the formula: mass (g) = moles × molar mass (g/mol). Substitute the values: mass of FeCl3 = 0.071 moles × 162.5 g/mol.
Step 8: Perform the calculation to find the mass of FeCl3 produced, which is approximately 23 grams.

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