If a bag contains 4 red, 3 blue, and 5 green balls, what is the probability of drawing a green ball?
Practice Questions
1 question
Q1
If a bag contains 4 red, 3 blue, and 5 green balls, what is the probability of drawing a green ball?
1/3
1/4
5/12
5/10
Total balls = 4 + 3 + 5 = 12. Probability of green ball = 5/12.
Questions & Step-by-step Solutions
1 item
Q
Q: If a bag contains 4 red, 3 blue, and 5 green balls, what is the probability of drawing a green ball?
Solution: Total balls = 4 + 3 + 5 = 12. Probability of green ball = 5/12.
Steps: 7
Step 1: Count the number of red balls in the bag. There are 4 red balls.
Step 2: Count the number of blue balls in the bag. There are 3 blue balls.
Step 3: Count the number of green balls in the bag. There are 5 green balls.
Step 4: Add the number of all the balls together. 4 red + 3 blue + 5 green = 12 total balls.
Step 5: Identify how many of the total balls are green. There are 5 green balls.
Step 6: To find the probability of drawing a green ball, divide the number of green balls by the total number of balls. This is 5 (green balls) divided by 12 (total balls).
Step 7: Write the probability as a fraction: Probability of drawing a green ball = 5/12.
