What is the product when propan-2-one reacts with iodine in the presence of a ba

What is the product when propan-2-one reacts with iodine in the presence of a base?

What is the product when propan-2-one reacts with iodine in the presence of a base?

Step 1: Identify the starting compound, which is propan-2-one (also known as acetone).
Step 2: Understand that propan-2-one has a carbonyl group (C=O) that can react with iodine.
Step 3: Recognize that the presence of a base (like sodium hydroxide) helps facilitate the reaction.
Step 4: The base deprotonates the alpha hydrogen of propan-2-one, making it more reactive.
Step 5: Iodine (I2) reacts with the deprotonated propan-2-one to form an intermediate compound.
Step 6: This intermediate undergoes further reactions, ultimately leading to the formation of iodoform (CHI3).
Step 7: The final product, iodoform, is a yellow solid that can be identified by its distinct smell.

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