What is the bond order of the O2 molecule according to Molecular Orbital Theory?

Practice Questions

Q1
What is the bond order of the O2 molecule according to Molecular Orbital Theory?
  1. 1
  2. 2
  3. 3
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Questions & Step-by-Step Solutions

What is the bond order of the O2 molecule according to Molecular Orbital Theory?
  • Step 1: Determine the total number of electrons in the O2 molecule. Each oxygen atom has 6 electrons, and since there are 2 oxygen atoms, the total is 6 + 6 = 12 electrons.
  • Step 2: Understand the arrangement of these electrons in molecular orbitals. The first 10 electrons fill the bonding orbitals, and the remaining 2 electrons fill the antibonding orbitals.
  • Step 3: Count the number of bonding and antibonding electrons. There are 10 bonding electrons and 2 antibonding electrons.
  • Step 4: Calculate the bond order using the formula: Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2.
  • Step 5: Plug in the numbers: Bond Order = (10 - 2) / 2 = 8 / 2 = 4.
  • Step 6: Correct the calculation: The correct number of antibonding electrons is actually 6, so Bond Order = (10 - 6) / 2 = 4 / 2 = 1.
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