How many grams of KCl can be produced from the reaction of 10 g of K with excess Cl2?

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Q: How many grams of KCl can be produced from the reaction of 10 g of K with excess Cl2?

Solution: 10 g of K = 0.25 moles. K + Cl2 → KCl, so 0.25 moles of KCl = 0.25 * 74.5 g = 18.625 g.

Steps: 9

Step 1: Calculate the number of moles of K (potassium) in 10 grams. Use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of K is approximately 39.1 g/mol.
Step 2: Substitute the values into the formula: moles of K = 10 g / 39.1 g/mol.
Step 3: Perform the calculation to find the number of moles of K.
Step 4: Write the balanced chemical equation for the reaction: K + Cl2 → KCl.
Step 5: From the balanced equation, note that 1 mole of K produces 1 mole of KCl.
Step 6: Since you have calculated the moles of K, you can conclude that the same number of moles of KCl will be produced.
Step 7: Calculate the mass of KCl produced using the formula: mass (g) = moles × molar mass (g/mol). The molar mass of KCl is approximately 74.5 g/mol.
Step 8: Substitute the number of moles of KCl into the formula: mass of KCl = moles of KCl × 74.5 g/mol.
Step 9: Perform the calculation to find the mass of KCl produced.