What is the volume of CO2 produced at STP when 2 moles of C2H5OH are completely

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Question: What is the volume of CO2 produced at STP when 2 moles of C2H5OH are completely combusted?

Options:

Correct Answer: 44.8 L

Solution:

C2H5OH + 3O2 → 2CO2 + 3H2O. 2 moles of C2H5OH produce 4 moles of CO2. Volume = 4 * 22.4 L = 89.6 L.

What is the volume of CO2 produced at STP when 2 moles of C2H5OH are completely combusted?

What is the volume of CO2 produced at STP when 2 moles of C2H5OH are completely combusted?

Step 1: Write the balanced chemical equation for the combustion of ethanol (C2H5OH). The equation is: C2H5OH + 3O2 → 2CO2 + 3H2O.
Step 2: Identify how many moles of CO2 are produced from the combustion of 1 mole of C2H5OH. From the equation, 1 mole of C2H5OH produces 2 moles of CO2.
Step 3: Calculate how many moles of CO2 are produced from 2 moles of C2H5OH. Since 1 mole produces 2 moles, 2 moles will produce 2 * 2 = 4 moles of CO2.
Step 4: Use the volume of 1 mole of gas at STP, which is 22.4 liters. Multiply the number of moles of CO2 (4 moles) by the volume of 1 mole (22.4 L).
Step 5: Calculate the total volume of CO2 produced: 4 moles * 22.4 L/mole = 89.6 L.

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