In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 10 g of Fe?
Practice Questions
1 question
Q1
In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 10 g of Fe?
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10 g of Fe = 0.18 moles. 2 moles of Fe produce 2 moles of FeCl3. 0.18 moles of FeCl3 = 0.18 * 162.5 g = 29.25 g.
Questions & Step-by-step Solutions
1 item
Q
Q: In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 10 g of Fe?
Solution: 10 g of Fe = 0.18 moles. 2 moles of Fe produce 2 moles of FeCl3. 0.18 moles of FeCl3 = 0.18 * 162.5 g = 29.25 g.
Steps: 8
Step 1: Calculate the number of moles of Fe in 10 grams. Use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of Fe is approximately 55.85 g/mol.
Step 2: Substitute the values into the formula: moles of Fe = 10 g / 55.85 g/mol.
Step 3: Perform the calculation to find the number of moles of Fe. This gives you approximately 0.18 moles of Fe.
Step 4: Look at the balanced chemical equation: 2Fe + 3Cl2 → 2FeCl3. This shows that 2 moles of Fe produce 2 moles of FeCl3.
Step 5: Since 2 moles of Fe produce 2 moles of FeCl3, 0.18 moles of Fe will produce the same amount of FeCl3, which is also 0.18 moles of FeCl3.
Step 6: Calculate the mass of FeCl3 produced. The molar mass of FeCl3 is approximately 162.5 g/mol.
Step 7: Use the formula: mass = moles × molar mass. Substitute the values: mass of FeCl3 = 0.18 moles × 162.5 g/mol.
Step 8: Perform the calculation to find the mass of FeCl3 produced, which is approximately 29.25 grams.
