If 10 g of Na reacts with excess Cl2, what is the mass of NaCl produced?
Practice Questions
1 question
Q1
If 10 g of Na reacts with excess Cl2, what is the mass of NaCl produced?
58.5 g
10 g
20 g
30 g
10 g of Na = 0.43 moles. Na + Cl2 → NaCl, so 0.43 moles of NaCl = 0.43 * 58.5 g = 25.2 g.
Questions & Step-by-step Solutions
1 item
Q
Q: If 10 g of Na reacts with excess Cl2, what is the mass of NaCl produced?
Solution: 10 g of Na = 0.43 moles. Na + Cl2 → NaCl, so 0.43 moles of NaCl = 0.43 * 58.5 g = 25.2 g.
Steps: 6
Step 1: Determine the molar mass of sodium (Na). The molar mass of Na is approximately 23 g/mol.
Step 2: Calculate the number of moles of Na in 10 g. Use the formula: moles = mass (g) / molar mass (g/mol). So, moles of Na = 10 g / 23 g/mol = 0.43 moles.
Step 3: Write the balanced chemical equation for the reaction: Na + Cl2 → NaCl. This shows that 1 mole of Na produces 1 mole of NaCl.
Step 4: Since we have 0.43 moles of Na, it will produce 0.43 moles of NaCl because the ratio is 1:1.
Step 5: Determine the molar mass of NaCl. The molar mass of NaCl is approximately 58.5 g/mol (23 g/mol for Na + 35.5 g/mol for Cl).
Step 6: Calculate the mass of NaCl produced using the formula: mass = moles × molar mass. So, mass of NaCl = 0.43 moles × 58.5 g/mol = 25.2 g.
