What is the value of the equilibrium constant Kc for the reaction A + B ⇌ C at 25°C if the concentrations are [A] = 0.1 M, [B] = 0.2 M, and [C] = 0.3 M?
Practice Questions
1 question
Q1
What is the value of the equilibrium constant Kc for the reaction A + B ⇌ C at 25°C if the concentrations are [A] = 0.1 M, [B] = 0.2 M, and [C] = 0.3 M?
0.5
1.0
1.5
2.0
Kc = [C]/([A][B]) = 0.3/(0.1*0.2) = 1.5
Questions & Step-by-step Solutions
1 item
Q
Q: What is the value of the equilibrium constant Kc for the reaction A + B ⇌ C at 25°C if the concentrations are [A] = 0.1 M, [B] = 0.2 M, and [C] = 0.3 M?
Solution: Kc = [C]/([A][B]) = 0.3/(0.1*0.2) = 1.5
Steps: 7
Step 1: Write down the balanced chemical equation: A + B ⇌ C.
Step 2: Identify the concentrations given: [A] = 0.1 M, [B] = 0.2 M, [C] = 0.3 M.
Step 3: Write the formula for the equilibrium constant Kc: Kc = [C] / ([A] * [B]).
Step 4: Substitute the values into the formula: Kc = 0.3 / (0.1 * 0.2).
Step 5: Calculate the denominator: 0.1 * 0.2 = 0.02.
Step 6: Now divide the concentration of C by the result from Step 5: Kc = 0.3 / 0.02.
