A 2 kg object is dropped from a height of 5 m. What is the potential energy at the top?

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Q: A 2 kg object is dropped from a height of 5 m. What is the potential energy at the top?

Solution: Potential energy = mgh = 2 kg × 9.8 m/s² × 5 m = 98 J.

Steps: 7

Step 1: Identify the mass of the object. In this case, the mass (m) is 2 kg.
Step 2: Identify the height from which the object is dropped. The height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. The value of g is approximately 9.8 m/s².
Step 4: Use the formula for potential energy, which is PE = mgh.
Step 5: Substitute the values into the formula: PE = 2 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 2 × 9.8 × 5 = 98 J.
Step 7: Conclude that the potential energy at the top is 98 Joules.