Question: A 1 kg mass is dropped from a height of 10 m. What is the speed just before it hits the ground?
Options:
Correct Answer: 10 m/s
Solution:
Using conservation of energy, potential energy at height = kinetic energy just before hitting the ground. mgh = 0.5mv^2. Solving gives v = sqrt(2gh) = sqrt(2*9.8*10) = 14 m/s.