A pendulum swings from a height of 5 m. What is the speed at the lowest point of the swing?
Practice Questions
1 question
Q1
A pendulum swings from a height of 5 m. What is the speed at the lowest point of the swing?
5 m/s
10 m/s
15 m/s
20 m/s
Using conservation of energy, potential energy at the top = kinetic energy at the bottom. mgh = 0.5mv^2. Solving gives v = sqrt(2gh) = sqrt(2*9.8*5) = 10 m/s.
Questions & Step-by-step Solutions
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Q
Q: A pendulum swings from a height of 5 m. What is the speed at the lowest point of the swing?
Solution: Using conservation of energy, potential energy at the top = kinetic energy at the bottom. mgh = 0.5mv^2. Solving gives v = sqrt(2gh) = sqrt(2*9.8*5) = 10 m/s.
