A block of mass 2 kg is released from a height of 10 m. What is its speed just before it hits the ground?
Practice Questions
1 question
Q1
A block of mass 2 kg is released from a height of 10 m. What is its speed just before it hits the ground?
0 m/s
10 m/s
14 m/s
20 m/s
Using conservation of energy, potential energy at height = kinetic energy just before hitting the ground. mgh = 0.5mv^2. Solving gives v = sqrt(2gh) = sqrt(2*9.8*10) = 14 m/s.
Questions & Step-by-step Solutions
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Q
Q: A block of mass 2 kg is released from a height of 10 m. What is its speed just before it hits the ground?
Solution: Using conservation of energy, potential energy at height = kinetic energy just before hitting the ground. mgh = 0.5mv^2. Solving gives v = sqrt(2gh) = sqrt(2*9.8*10) = 14 m/s.
